Question
Simplify: $\left(\frac{1}{2}+\frac{2}{3}\right) \div\left(\frac{3}{4}-\frac{2}{9}\right)$
✓
Answer
$\begin{aligned} & \left(\frac{1}{2}+\frac{2}{3}\right) \div\left(\frac{3}{4}-\frac{2}{9}\right) \\ & =\frac{3+4}{6} \div \frac{27-8}{36} \text {..(Using BODMAS) } \\ & =\frac{7}{6} \div \frac{19}{36} \\ & =\frac{7}{6} \times \frac{36}{19}=\frac{42}{19}=2 \frac{4}{19}\end{aligned}$
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