Question
Simplify the expression:
$\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$
$\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$
✓
Answer
$\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$
We need to apply distributive law to find value of $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$ $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right) = 3\left( {3 - \sqrt 3 } \right) + \sqrt 3 \left( {3 - \sqrt 3 } \right)$
$= 9 - 3\sqrt 3 + 3\sqrt 3 - 3$
= 6
Therefore, on simplifying $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$, we get 6.
We need to apply distributive law to find value of $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$ $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right) = 3\left( {3 - \sqrt 3 } \right) + \sqrt 3 \left( {3 - \sqrt 3 } \right)$
$= 9 - 3\sqrt 3 + 3\sqrt 3 - 3$
= 6
Therefore, on simplifying $\left( {3 + \sqrt 3 } \right)\left( {3 - \sqrt 3 } \right)$, we get 6.
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