Question
Simplify using following identity$ :(a \pm b)\left(a^2 \pm a b+b^2\right)=a^3 \pm b^3$
$ (2 x+3 y)\left(4 x^2+6 x y+9 y^2\right)$
$ (2 x+3 y)\left(4 x^2+6 x y+9 y^2\right)$
✓
Answer
$( 2x + 3y )( 4x^2 + 6xy + 9y^2)$
$= ( 2x + 3y )[ (2x)^2 - (2x)(3y) + (3y)^2]$
$= (2x)^3 + (3y)^3$
$= 8x^3 + 27y^3$
$= ( 2x + 3y )[ (2x)^2 - (2x)(3y) + (3y)^2]$
$= (2x)^3 + (3y)^3$
$= 8x^3 + 27y^3$
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