^ -1 (1-x)-2 ^ -1 x= 2 1. 0 2. 1 2 3. 0,1 2 4. -1 2 - Vidyadip

Question

$\sin^{-1}(1-\text{x})-2\sin^{-1}\text{x}=\frac{\pi}{2}$

$0$
$\frac{1}{2}$
$0,\frac{1}{2}$
$-\frac{1}{2}$

✓

Answer

$0$

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