163^o347^o + 73^o167^o = - Vidyadip

MCQ

$\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o} = $

A
$0$
✓
$1/2$
C
$1$
D
None of these

✓

Answer

Correct option: B.

$1/2$

b
(b) $\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o}$

$ = \sin ({180^o} - {17^o})\cos ({360^o} - {13^o}) + \cos ({90^o} - {17^o}) \sin ({180^o} - {13^o})$

$ = \sin {17^o}\cos {13^o} + \cos {17^o}\sin {13^o}$

$ =\sin {30^o} = 1/2$.

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