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Inverse Trigonometric Functions — Maths STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceMathsInverse Trigonometric Functions2 Marks
Question
$\sin^{-1}\Big\{\cos\Big(\sin^{-1}\frac{\sqrt3}{2}\Big)\Big\}$
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Answer

$\sin^{-1}\Big\{\cos\Big(\sin^{-1}\frac{\sqrt3}{2}\Big)\Big\}$
$=\sin^{-1}\Big\{\cos\Big(\frac{\pi}{3}\Big)\Big\}$
$=\sin^{-1}\Big\{\frac{\sqrt3}{2}\Big\}=\frac{\pi}{6}$

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