MCQ
$\sin \left( {\frac{\pi }{{10}}} \right)\sin \left( {\frac{{3\pi }}{{10}}} \right) = $
- A$1/2$
- B$-1/2$
- ✓$1/4$
- D$1$
$ = \sin 18^\circ .\cos 36^\circ = \frac{{\sqrt 5 - 1}}{4}.\frac{{\sqrt 5 + 1}}{4} = \frac{1}{4}$.
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$2a + b + c + d + e = 6$
$a + 2b + c + d + e = 12$
$a + b + 2c + d + e = 24$
$a + b + c + 2d + e = 48$
$a + b + c + d + 2e = 96$ ,
then $|c|$ is equal to