MCQ
$\sin \left(\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right)$ is equal to
  • A
    $\frac{1}{2}$
  • B
    $\frac{1}{3}$
  • C
    $\frac{1}{4}$
  • 1

Answer

Correct option: D.
1
(D) $\sin \left(\frac{\pi}{3}-\sin ^{-1}\left(-\frac{1}{2}\right)\right)=\sin \left(\frac{\pi}{3}+\sin ^{-1}\left(\frac{1}{2}\right)\right)$
$=\sin \left(\frac{\pi}{3}+\frac{\pi}{6}\right)=\sin \frac{\pi}{2}=1$

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