MCQ
$\sin[\cot^{-1}\{\cos(\tan^{-1}\text{x})\}]=$
  • $\sqrt{\frac{\text{x}^2+1}{\text{x}^2+2}}$
  • B
    $\sqrt{\frac{\text{x}^2-1}{\text{x}^2-2}}$
  • C
    $\sqrt{\frac{\text{x}-1}{\text{x}-2}}$
  • D
    $\sqrt{\frac{\text{x}+1}{\text{x}+2}}$

Answer

Correct option: A.
$\sqrt{\frac{\text{x}^2+1}{\text{x}^2+2}}$

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