MCQ
સમીકરણ $\tan \theta = \cot \alpha $ નો વ્યાપક ઉકેલ મેળવો.
- ✓$\theta = n\pi + \frac{\pi }{2} - \alpha $
- B$\theta = n\pi - \frac{\pi }{2} + \alpha $
- C$\theta = n\pi + \frac{\pi }{2} + \alpha $
- D$\theta = n\pi - \frac{\pi }{2} - \alpha $
$\Rightarrow \tan \theta = \tan \left( {\frac{\pi }{2} - \alpha } \right)$
$ \Rightarrow $ $\theta = n\pi + \frac{\pi }{2} - \alpha $.
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