MCQ
$S_{N_1}$ reaction on optically active substrates mainly gives:
- ARetention in configuration
- BInversion in configuration
- ✓Racemic product
- DNo product
✓
Answer
Correct option: C.
Racemic product
Since the nucleophile attacks the carbocation only after the leaving group has departed, in $S_{N_1},$ there is no need for back$-$side attack.The carbocation and its substituents are all in the same plane $($Figure $1),$ meaning that the nucleophile can attack from either side.
As a result, both enantiomers are formed in a $S_{N_1}$ reaction, leading to a racemic mixture of both enantiomers.
As a result, both enantiomers are formed in a $S_{N_1}$ reaction, leading to a racemic mixture of both enantiomers.
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