- ✓$5.1 \times {10^{ - 5}}\,M$
- B$7.1 \times {10^{ - 8}}\,M$
- C$4.1 \times {10^{ - 5}}\,M$
- D$8.1 \times {10^{ - 7}}\,M$
$\therefore \,[CO_3^ - ] = 1.0 \times {10^{ - 4}}\,M$
$i.e.\,\,\,s = 1.0 \times {10^{ - 4}}\,M$
At equilibrium
$[B{a^{ + + }}][CO_3^ - ] = {K_{sp}}\,of\,BaC{O_3}$
$[B{a^{ + + }}] = \frac{{{K_{sp}}}}{{[CO_3^ - ]}} = \frac{{5.1 \times {{10}^{ - 9}}}}{{1.0 \times {{10}^{ - 4}}}}$
$ = 5.1 \times {10^{ - 5}}\,M$
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$(I)\, CO^{2-}_3$ $(II)\, XeF_4$ $(III)\, I^-_3$ $(IV)\, NCl_3$ $(V)$ $BeCl_2$
$(A)$ Addition of an electron in $O_2$ decreases bond order
$(B)$ Addition of an electron in $O_2$ increases bond order
$(C)$ Removal of an electron from $O_2$ increases bond length
$(D)$ Removal of an electron from $O_2$ decreases bond length
