MCQ
Solubility of $Ba{F_2}$ in a solution $Ba{(N{O_3})_2}$ will be represents by the concentration term
- A$[B{a^{ + 2}}]$
- B$[{F^ - }]$
- ✓$\frac{1}{2}[{F^ - }]$
- D$2\,[NO_3^ - ]$
The expression for the solubility product is given by,
$K _{ sp }=\left[ Ba ^{2+}\right]\left[ F ^{-}\right]^2$
The concentration of fluoride ions in the solution is as follows:
$\left[ F ^{-}\right]=2 s$
Thus, $s=\frac{1}{2}\left[ F ^{-}\right]$
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| List $I$ (Mixture) | List $II$ (Separation Technique) |
| $A$ $CHCl _3+ C _6 H _5 NH _2$ | $I$ Steam distillation |
| $B$ $C _6 H _{14}+ C _5 H _{12}$ | $II$ Differential extraction |
| $C$ $C _6 H _5 NH _2+ H _2 O$ | $III$ Distillation |
| $D$ Organic compound in $H _2 O$ | $IV$ Fractional distillation |
$(A)$ $C _6 H _5 OH$ and $C _6 H _5 COOH$
$(B)$ $C _6 H _5 COOH$ and $C _6 H _5 CH _2 OH$
$(C)$ $C _6 H _5 CH _2 OH$ and $C _6 H _5 OH$
$(D)$ $C _6 H _5 CH _2 OH$ and $C _6 H _5 CH _2 COOH$
$I = -3.04\,V$,
$II = -1.90\,V$,
$III = 0\,V$,
$IV = 1.90\,V$