- A$[B{a^{ + 2}}]$
- B$[{F^ - }]$
- ✓$\frac{1}{2}[{F^ - }]$
- D$2\,[NO_3^ - ]$
The expression for the solubility product is given by,
$K _{ sp }=\left[ Ba ^{2+}\right]\left[ F ^{-}\right]^2$
The concentration of fluoride ions in the solution is as follows:
$\left[ F ^{-}\right]=2 s$
Thus, $s=\frac{1}{2}\left[ F ^{-}\right]$
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$(i)$ $P{b^{2 + }} > P{b^{4 + }},T{l^ + } < T{l^{3 + }}$ $(ii)$ $Bi^{3+} < Sb^{3+} , Sn^{2+} < sn^{4+}$
$(iii)$ $P{b^{2 + }} > P{b^{4 + }},B{i^{3 + }} > B{i^{5 + }}$ $(iv)$ $T{l^{3 + }} < I{n^{3 + }},S{n^{2 + }} > S{n^{4 + }}$
$(v)$ $S{n^{2 + }} < P{b^{2 + }},S{n^{4 + }} > P{b^{4 + }}$ $(vi)$ $S{n^{2 + }} < P{b^{2 + }},S{n^{4 + }} < P{b^{4 + }}$
$(A) -CN$ $(B) -NO_2$ $(C) -NH_2$ $(D) -F$
