MCQ
Solution of $\bigg|\text{x}+\frac{1}{\text{x}}\bigg|<4 $ is:
- A$\big(2-3, 2+3\big)\cup\big(-2-3-2+3\big)$
- B$\text{R}\big(2-3, 2+3\big)$
- C$\text{R}-\big(-2-3-2 + 3\big)$
- D$\text{None of these}$
✓
Answer
- $\big(2-3, 2+3\big)\cup\big(-2-3-2+3\big)$
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