Solution of 3 x d x is - Vidyadip

MCQ

Solution of $\int \sin 3 x\ d x$ is

A
$\frac{1}{3} \cos 3 x+c$
B
$\frac{1}{3} \sin 3 x+c$
C
$-\frac{1}{3} \sin 3 x+c$
✓
$-\cos 3 x+c$

✓

Answer

Correct option: D.

$-\cos 3 x+c$

$-\cos 3 x+c$

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