Question
Solve : $13(x - 4) - 3(x - 9) - 5(x + 4) = 0$

Answer

$13(x-4)-3(x-9)-5(x+4)=0$
$ \Rightarrow 13 x-52-3 x+27-5 x-20=0$
$ \Rightarrow 13 x-3 x-5 x-52+27-20=0$
$ \Rightarrow 13 x-8 x-72+27=0$
$ \Rightarrow 5 x-45=0$
Dividing by $5$ ,
$\frac{5 x}{5}-\frac{45}{5}=0 $
$\Rightarrow \mathrm{x}-9=0 $
$\Rightarrow x=9$
Verification:
$\text { L.H.S. }=13(x-4)-3(x-9)-5(x+4)$
$ =13(9-4)-3(9-9)-5(9+4)$
$ =13 \times 5-3 \times 0-5 \times 13$
$ =65-0-65=0=\text { R.H.S. }$

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