Question
Solve: $5 x-\left(4 x+\frac{5 x-4}{7}\right)=\frac{4 x-14}{3}$
✓
Answer
$ 5 x-\left(4 x+\frac{5 x-4}{7}\right)=\frac{4 x-14}{3}$
$ 5 x-\left(\frac{28 x+5 x-4}{7}\right)=\frac{4 x-14}{3}$
$ \frac{35 x-33 x+4}{7}=(4 x-14)$
$ 6 x+12=28 x-98$
$ 22 x=98+12$
$ x=\frac{110}{22}=5$
$ 5 x-\left(\frac{28 x+5 x-4}{7}\right)=\frac{4 x-14}{3}$
$ \frac{35 x-33 x+4}{7}=(4 x-14)$
$ 6 x+12=28 x-98$
$ 22 x=98+12$
$ x=\frac{110}{22}=5$
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