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Playing with Numbers — Maths STD 8 — Question

Maharashtra BoardEnglish MediumSTD 8MathsPlaying with Numbers3 Marks
Question
Solve Cryptarithms.
$\ \ \ \ \ \ \ \ \ \ \ \text{A}\ \ \ \ \text{B}\\\ \ \ \ \ \underline{+\ \ \ 3\ \ \ \ \ 7\ }\\\ \ \ \ \ {\ \ \ \ \ \ 9\ \ \ \ \text{A}\ }$
✓

Answer

Two possibilities of A are:
  1. If $\text{B}+7<9,$
$\text{A}=6$

But clearly, if A = 6,

$\text{B}+7\geq9;$

It is impossible
  1. If $\text{B}+7\geq9,$
A = 5 and B + 7 = 5

Clearly, B = 8

$\therefore$ A = 5, B = 8

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