Question
Solve : $\frac{2 \mathrm{x}+3}{5}>\frac{4 \mathrm{x}-1}{2}, \mathrm{x} \in \mathrm{W}$.
✓
Answer
$\frac{2 x+3}{5}>\frac{4 x-1}{2}, x \in W$
$ \Rightarrow 2(2 x+3)>5(4 x-1)$
$ \Rightarrow 4 x+6>20 x-5$
$ \Rightarrow 4 x-20 x>-5-6$
$ \Rightarrow-16 x>-11$
$\Rightarrow x<\frac{-11}{-16} ($Dividing by $-16 )$
$\Rightarrow \mathrm{x}<\frac{11}{16}$
$\therefore \mathrm{x}=0$
$\therefore$ Solution set $=\{0\}$
$ \Rightarrow 2(2 x+3)>5(4 x-1)$
$ \Rightarrow 4 x+6>20 x-5$
$ \Rightarrow 4 x-20 x>-5-6$
$ \Rightarrow-16 x>-11$
$\Rightarrow x<\frac{-11}{-16} ($Dividing by $-16 )$
$\Rightarrow \mathrm{x}<\frac{11}{16}$
$\therefore \mathrm{x}=0$
$\therefore$ Solution set $=\{0\}$
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