Question
Solve: $\frac{2 x-3}{4} \geq \frac{1}{2}, x \in\{0,1,2, \ldots, 8\}$

Answer

$\begin{aligned} & \frac{2 x-3}{4} \geq \frac{1}{2} \\ & \Rightarrow 2 x-3 \geq \frac{4}{2} \\ & \Rightarrow 2 x-3 \geq 2 \\ & \Rightarrow 2 x \geq 2+3 \\ & \Rightarrow 2 x \geq 5 \\ & \Rightarrow x \geq \frac{5}{2} \\ & \because x \in\{0,1,2, \ldots \ldots . . . .8\} \\ & \therefore \text { Solution set }=\{3,4,5,6,7,8\} .\end{aligned}$

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