Question
Solve : $\frac{3 x-2}{4}-\frac{2 x+3}{3}=\frac{2}{3}-x$
✓
Answer
$\frac{3 \mathrm{x}-2}{4}-\frac{2 \mathrm{x}+3}{3}=\frac{2}{3}-\mathrm{x}$
$ =\frac{3 \mathrm{x}-2}{4}-\frac{2 \mathrm{x}+3}{3}=\frac{2}{3}-\frac{\mathrm{x}}{1}$
$ =\frac{3(3 \mathrm{x}-2)-4(2 \mathrm{x}+3)}{12}=\frac{2 \times 1}{3 \times 1}-\frac{\mathrm{x} \times 3}{1 \times 3}$
$=\frac{9 x-6-8 x-12}{12}=\frac{2-3 x}{3}$
$ =\frac{x-18}{12}=\frac{2-3 x}{3}$
$ =3(x-18)=12(2-3 x)$
$ =3 x-54=24-36 x$
$ =3 x+36 x=24+54$
$ =39 x=78$
$\mathrm{x}=\frac{78}{39}=2$
$\therefore x=2$
$ =\frac{3 \mathrm{x}-2}{4}-\frac{2 \mathrm{x}+3}{3}=\frac{2}{3}-\frac{\mathrm{x}}{1}$
$ =\frac{3(3 \mathrm{x}-2)-4(2 \mathrm{x}+3)}{12}=\frac{2 \times 1}{3 \times 1}-\frac{\mathrm{x} \times 3}{1 \times 3}$
$=\frac{9 x-6-8 x-12}{12}=\frac{2-3 x}{3}$
$ =\frac{x-18}{12}=\frac{2-3 x}{3}$
$ =3(x-18)=12(2-3 x)$
$ =3 x-54=24-36 x$
$ =3 x+36 x=24+54$
$ =39 x=78$
$\mathrm{x}=\frac{78}{39}=2$
$\therefore x=2$
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