MCQ
Solve $\sqrt{3\text{x}^2}+\text{x}+\sqrt{3}=0$
  • $\frac{-1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
  • B
    $\frac{1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
  • C
    $\frac{1\pm\sqrt{11}}{6\sqrt{3}}$
  • D
    $\frac{-1\pm\sqrt{11}}{6\sqrt{3}}$

Answer

Correct option: A.
$\frac{-1\pm\text{i}\sqrt{11}}{6\sqrt{3}}$
$\sqrt{3\text{x}^2}+\text{x}+\sqrt{3}=0$
$\Rightarrow​​3\text{x}^2+\sqrt{3\text{x}}+3=0$
$\Rightarrow\text{D}=(\sqrt{3})^2-4.3.3=3-36=-33$
Since $\text{D}\leq0,$ imaginary roots are there.

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