Question
Solve:
$\tan^{-1}\text{x}+2\cot^{-1}\text{x}=\frac{2\pi}{3}$
$\tan^{-1}\text{x}+2\cot^{-1}\text{x}=\frac{2\pi}{3}$
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$\tan \left(45^{\circ} 40^{\circ}\right)$, given that $1^{\circ}=0.0175^{\circ}$.