$\frac{\text{2x}}{5}-\frac{\text{x}}{2}=\frac{5}{2}$
Or, $\frac{\text{4x-5x}}{10}=\frac{5}{2}$ [Taking L.C.M. as 10]
$\Rightarrow\frac{\text{x}}{10}=\frac{5}{2}$
$\Rightarrow\frac{\text{x}}{10}\times(-10)=\frac{5}{2}\times(-10)$ [Multiplying both the sides by (-10)]
$\text{x}=-25$
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