Question
Solve the equation: $3s + 12 = 0$
✓
Answer
The given equation is
$3s + 12 = 0$
Subtract $–12$ from both sides
$3s + 12 – 12 = 0 – 12$
$\therefore 3s = – 12$
Divide both sides by $3,$
$\frac{35}{3}=-\frac{12}{3}$
$\therefore s = –4$
It is the required solution
$3s + 12 = 0$
Subtract $–12$ from both sides
$3s + 12 – 12 = 0 – 12$
$\therefore 3s = – 12$
Divide both sides by $3,$
$\frac{35}{3}=-\frac{12}{3}$
$\therefore s = –4$
It is the required solution
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