Question
Solve the following differential equation
$\frac{\text{dy}}{\text{dx}}=(\text{e}^\text{x}+1)\text{y}$
$\frac{\text{dy}}{\text{dx}}=(\text{e}^\text{x}+1)\text{y}$
$\Rightarrow\frac{1}{\text{y}}\text{dy}=(\text{e}^\text{x}+1)\text{dx}$
Integrating both sides, we get
$\frac{1}{\text{y}}\text{dy}=(\text{e}^\text{x}+1)\text{dx}$
$\Rightarrow\log|\text{y}|=\text{e}^\text{x}+\text{x} +\text{C}$ Hence, $\Rightarrow\log|\text{y}|=\text{e}^\text{x}+\text{x} +\text{C}$ is the required solution.Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\text{f}(\text{x})=[\text{x}]\text{ on }\text{x}\in[5,9]$
$\text{f}(\text{x})=[\text{x}]\text{ on }\text{x}\in[-2,2]$
Can you say something about the converse of Rolle's Theorem from these functions?
$\int\frac{\cos\text{x}-\sin\text{x}}{\sqrt{8-\sin2\text{x}}}\text{ dx}$