Question
Solve the following differential equations:$2\text{x}\frac{\text{dy}}{\text{dx}}=3\text{y},\text{y}(1)=2$

Answer

$2\text{x}\frac{\text{dy}}{\text{dx}}=3\text{y},\text{y}(1)=2$
$\int\frac{2\text{dy}}{\text{y}}=\int\frac{3\text{dx}}{\text{x}}$
$2\log|\text{y}|=3\log|\text{x}|+\log\text{C}$
$\text{y}^2=\text{x}^3\text{C}...(1)$
Put $\text{x}=1,\text{y}=2$
$4=\text{C}$
Put $\text{C}=4$ in equation (1),
$\text{y}^2=4\text{x}^3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Prove the following Exercise:
$\int^{1}_{0}\sin^{-1}\text{x dx}=\frac{\pi}{2}-1$
What is the value of $\cos^{-1}\Big(\cos\frac{2\pi}{3}\Big)+\sin^{-1}\Big(\sin\frac{2\pi}{3}\Big)$
If $A^{-1}=\left[\begin{array}{ccc}3 & -1 & 1 \\ -15 & 6 & -5 \\ 5 & -2 & 2\end{array}\right]$ and $B=\left[\begin{array}{ccc}1 & 2 & -2 \\ -1 & 3 & 0 \\ 0 & -2 & 1\end{array}\right]$ find $( A B)^{-1}$
If $\int\text{e}^{\text{x}}(\tan\text{x}+1)\sec\text{x dx}=\text{e}^{\text{x}}\text{ f}(\text{x})+\text{C},$ then write the value of f(x).
Show that the relation $R$ defined in the set $A$ of all triangles as $R = \{(T_1, T_2) : T_1$ is similar to $T_2\},$ is equivalence relation. Consider three right angle triangles $T_1$ with sides $3, 4, 5, T_2$ with sides $5, 12, 13$ and $T_3$ with sides $6, 8, 10.$ Which triangles among $T_1, T_2$ and $T_3$ are related?
Let $A = IR – \{3\}$ and $B = IR – \{1\}$. Consider the function $f: A \rightarrow B$ defined by $\text{f(x)}=\Bigg(\frac{\text{x - 2}}{\text{x - 3}}\Bigg)$. Show that fis one$-$one and onto and hence find $f^{–1}$.
Evaluate the following definite integrals:
$\int_{0}^\limits{1}\frac{1}{2\text{x}^2+\text{x}+1}\text{ dx}$
Find the angle between the following pair of lines:
  1. $\frac{\text{x}-2}{2}=\frac{\text{y}-1}{5}=\frac{\text{z}+3}{-3}\ \text{and}\ \frac{\text{x}+2}{-1}=\frac{\text{y}-4}{8}=\frac{\text{z}-5}{4}$
Show that the following planes are at right angles. $x - 2y + 4z = 10$ and $18x + 17y + 4z = 49$
The cartesian equation of a line AB are $\frac{2\text{x}-1}{\sqrt{3}}=\frac{\text{y}+2}{2}=\frac{\text{z}-3}{3}.$ Find the direction cosines of a line parallel to AB.