Question
Solve the following equation: $7 x+\frac{3}{x}=35 \frac{3}{5}$
✓
Answer
$7 x +\frac{3}{ x }=35 \frac{3}{5} $
$ 7 x ^2+3=\frac{178}{5} x$
$ 7 x ^2-\frac{178}{5} x +3=0 $
$x ^2-\frac{178}{35} x +\frac{3}{7}=0$
$x ^2-5 x -\frac{3}{35} x +\frac{3}{7}=0 $
$x ( x -5)-\frac{3}{35}( x -5)=0$
$( x -5)\left( x -\frac{3}{35}\right)=0$
$ x =5, x =\frac{3}{35}$
$ 7 x ^2+3=\frac{178}{5} x$
$ 7 x ^2-\frac{178}{5} x +3=0 $
$x ^2-\frac{178}{35} x +\frac{3}{7}=0$
$x ^2-5 x -\frac{3}{35} x +\frac{3}{7}=0 $
$x ( x -5)-\frac{3}{35}( x -5)=0$
$( x -5)\left( x -\frac{3}{35}\right)=0$
$ x =5, x =\frac{3}{35}$
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