Question
Solve the following equation for $A,$ if $2\ \sin 3\ A = 1$
✓
Answer
$2 \sin 3 A=1 $
$ \sin 3 A=\frac{1}{2} $
$ \sin 3 A=\sin 30^{\circ}$
$ 3 A=30^{\circ} $
$A=10^{\circ}$
$ \sin 3 A=\frac{1}{2} $
$ \sin 3 A=\sin 30^{\circ}$
$ 3 A=30^{\circ} $
$A=10^{\circ}$
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