Question
Solve the following equation : $\frac{4(y+2)}{5}=7+\frac{5 y}{13}$

Answer

$\Rightarrow \frac{4 y+8}{5}=7+\frac{5 y}{13}$
$\Rightarrow \frac{4 y+8}{5}=\frac{91+5 y}{13} \ldots ($by cross multiplying$)$
$\Rightarrow 13(4 y+8)=5(91+5 y)$
$\Rightarrow 52 y+104=455+25 y$
$\Rightarrow 52 y-25 y=455-104$
$\Rightarrow 27 y=351$
$\Rightarrow \mathrm{y}=\frac{351}{27}$
$\Rightarrow \mathrm{y}=13$

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