Question
Solve the following equations for x:
$7^{2\text{x}+3}=1$
$7^{2\text{x}+3}=1$
✓
Answer
We have,$\Rightarrow7^{2\text{x}+3}=1$
$\Rightarrow7^{2\text{x}+3}=7^0$
$\Rightarrow2\text{x}+3=0$
$\Rightarrow2\text{x}=-3$
$\Rightarrow\text{x}=-\frac{3}{2}$
$\Rightarrow7^{2\text{x}+3}=7^0$
$\Rightarrow2\text{x}+3=0$
$\Rightarrow2\text{x}=-3$
$\Rightarrow\text{x}=-\frac{3}{2}$
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