Question
Solve the following equations for x and give, in each case, your answer correct to 3 decimal places
$2x^2 + 11x + 4= 0$
$2x^2 + 11x + 4= 0$
✓
Answer
$2 x^2+11 x+4=0$
Here a= 2, b = 11 and c = 4
$\therefore x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$=\frac{-(11) \pm \sqrt{(11)^2-4(2)(4)}}{2(2)}$
$=\frac{-11 \pm \sqrt{(11)^2-4(2)(4)}}{2(2)}$
$=\frac{-11 \pm \sqrt{89}}{4}$
$=\frac{-11 \pm 9.433}{4}$
$=\frac{-11+9.433}{4}$ and $\frac{-11-9.433}{4}$
$=-0.392$ and -5.108
Here a= 2, b = 11 and c = 4
$\therefore x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a}$
$=\frac{-(11) \pm \sqrt{(11)^2-4(2)(4)}}{2(2)}$
$=\frac{-11 \pm \sqrt{(11)^2-4(2)(4)}}{2(2)}$
$=\frac{-11 \pm \sqrt{89}}{4}$
$=\frac{-11 \pm 9.433}{4}$
$=\frac{-11+9.433}{4}$ and $\frac{-11-9.433}{4}$
$=-0.392$ and -5.108
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