Solve the following equations : y 7 +y-4 3 =2 - Vidyadip

Question

Solve the following equations :

$\frac{y}{7}+\frac{y-4}{3}=2$

✓

Answer

$\begin{aligned} & \text {} \frac{y}{7}+\frac{y-4}{3}=2 \\ & \therefore \quad \frac{y \times 3}{7 \times 3}+\frac{(y-4) \times 7}{3 \times 7}=2 \\ & \therefore \quad \frac{3 y}{21}+\frac{7 y-28}{21}=2 \\ & \therefore \quad \frac{3 y+7 y-28}{21}=2 \\ & \therefore \quad \frac{10 y-28}{21}=2 \\ & \therefore \quad \frac{10 y-28}{21} \times 21=2 \times 21 \\ & \text {...[Multiplying both the sides by 21] } \\ & \therefore 10 y-28=42 \\ & \therefore \quad 10 y-28+28=42+28 \\ & \text {...[Adding } 28 \text { on both the sides] } \\ & \therefore \quad 10 y=70 \\ & \therefore \quad \frac{10 y}{10}=\frac{70}{10} \\ & \therefore \quad y=7 \\ & \end{aligned}$

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