Question
Solve the following linear in-equation and graph the solution set on a real number line:
$4 \frac{3}{4} \geq x +\frac{5}{6}>\frac{1}{3}, x \in R$

Answer

$4 \frac{3}{4} \geq x+\frac{5}{6} $
$ \frac{19}{4} \geq \frac{6 x+5}{6} $
$ 114 \geq 24 x+20 $
$114-20 \geq 24 x$
$ 94 \geq 24 x$
$x \leq 3 \frac{11}{12} $
$ \text { and }$
$x+\frac{5}{6}>\frac{1}{3} $
$ \frac{6 x+5}{6}>\frac{1}{3}$
$18 x+15>6$
$18 x>6-15$
$18 x>-9$
$x>-\frac{1}{2}$
Solution set $=\left[-\frac{1}{2}< x \leq 3 \frac{11}{12}\right]$

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