Question
Solve the following linear inequations in R:
$3\text{x}+9\geq-\text{x}+19$
$3\text{x}+9\geq-\text{x}+19$
✓
Answer
$3\text{x}+9\geq-\text{x}+19$
$\Rightarrow3\text{x}+\text{x}\geq19-9$
$\Rightarrow4\text{x}\geq10$
$\Rightarrow\text{x}\geq\frac{10}{4}=\frac{5}{2}$
$\therefore\Big[\frac{5}{2},\infty\Big)$ is the solution set.
$\Rightarrow3\text{x}+\text{x}\geq19-9$
$\Rightarrow4\text{x}\geq10$
$\Rightarrow\text{x}\geq\frac{10}{4}=\frac{5}{2}$
$\therefore\Big[\frac{5}{2},\infty\Big)$ is the solution set.
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