Question
Solve the following linear inequations in R: $\frac{\text{x}-1}{3}+4<\frac{\text{x}-5}{5}-2$

Answer

$\frac{\text{x}-1}{3}+4<\frac{\text{x}-5}{5}-2$ $\frac{\text{x}-1+12}{3}<\frac{\text{x}-5-10}{5}$ 5 (x - 1 + 12) < 3 (x - 5 - 10) 5(x + 11) < 3 (x - 15) 5x + 55 < 3x - 45 5x - 3x < -45 -55 2x < -100 x < -50 $\therefore$ The solution set is $(-\infty,-50)$

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