Solve the following quadratic equation: 48 x^2-13 x-1=0 - Vidyadip

Question

Solve the following quadratic equation:
$ 48 x^2-13 x-1=0 $

✓

Answer

$ 48 x^2-13 x-1=0 $
$ \Rightarrow 48 x^2-16 x+3 x-1=0 $
$ \Rightarrow 16 x(3 x-1)+1(3 x-1)=0 $
$ \Rightarrow(3 x-1)(16 x+1)=0 $
$ \Rightarrow 3 x-1=0 \text { or } 16 x+1=0$
$\Rightarrow\text{x}=\frac{1}{3}$ or $\text{x}=\frac{-1}{16}$
Hence, $\frac{-1}{16}$ and $\frac{1}{3}$ are the roots of the equation $48x^2- 13x - 1 = 0$

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