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Quadratic Equations — Maths STD 10 — Question

Gujarat BoardEnglish MediumSTD 10MathsQuadratic Equations2 Marks
Question
Solve the following quadratic equation:
$ 6 x^2+x-12=0 $
✓

Answer

$ 6 x^2+x-12=0 $
$ \Rightarrow 6 x^2+9 x-8 x-12=0 $
$ \Rightarrow 3 x(2 x+3)-4(2 x+3)=0 $
$ \Rightarrow(2 x+3)(3 x-4)=0 $
$ \Rightarrow 2 x+3=0 \text { or } 3 x-4=0$
$\Rightarrow\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{4}{3}$
Hence, $\frac{-3}{2}$ and $\frac{4}{3}$ are the roots of $ 6 x^2+x-12=0 $

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