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P-1 Quadratic Equations — Maths STD 10 — Question

Maharashtra BoardEnglish MediumSTD 10MathsP-1 Quadratic Equations4 Marks
Question
Solve the following quadratic equation.
m2 + 5m + 5 = 0
✓

Answer


$\begin{array}{l}m^2+5 m+5=0 \text { compare with } a x^2+b x+c=0 \\ \Rightarrow a=1, b=5 \text { and } c=5 \\ \therefore b^2-4 a c=5^2-4(1)(5) \\ =25-20 \\ =5 \\ x=\frac{-b \pm \sqrt{b^2-4 a c}}{2 a} \\ \Rightarrow x=\frac{-5 \pm \sqrt{5}}{2 \times 1}\end{array}$
$\begin{array}{l}\Rightarrow x=\frac{-5 \pm \sqrt{5}}{2} \\ \Rightarrow x=\frac{-5+\sqrt{5}}{2} \text { or } x=\frac{-5-\sqrt{5}}{2}\end{array}$

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