Question
Solve the following quadratic equation.
$m^2+5 m+5=0$
$m^2+5 m+5=0$
✓
Answer
$ m ^2+5 m+5=0 \text { compare with } ax ^2+ bx + c =0$
$ \Rightarrow a =1, b=5 \text { and } c=5 $
$ \therefore b ^2-4 ac =5^2-4(1)(5)$
$ =25-20$
$=5$
$ x =\frac{- b \pm \sqrt{b^2-4 a c}}{2 a } $
$ \Rightarrow x =\frac{-5 \pm \sqrt{5}}{2 \times 1} $
$ \Rightarrow x =\frac{-5 \pm \sqrt{5}}{2} $
$\Rightarrow x =\frac{-5+\sqrt{5}}{2} \text { or } x=\frac{-5-\sqrt{5}}{2}$
$ \Rightarrow a =1, b=5 \text { and } c=5 $
$ \therefore b ^2-4 ac =5^2-4(1)(5)$
$ =25-20$
$=5$
$ x =\frac{- b \pm \sqrt{b^2-4 a c}}{2 a } $
$ \Rightarrow x =\frac{-5 \pm \sqrt{5}}{2 \times 1} $
$ \Rightarrow x =\frac{-5 \pm \sqrt{5}}{2} $
$\Rightarrow x =\frac{-5+\sqrt{5}}{2} \text { or } x=\frac{-5-\sqrt{5}}{2}$
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