Question
Solve the following quadratic equations by factorization:
$5 x^2-3 x-2=0$
$5 x^2-3 x-2=0$
✓
Answer
We have,
$5 x^2-3 x-2=0$
$\Rightarrow 5 x^2-5 x+2 x-2=0$
$\Rightarrow 5 x(x-1)+2(x-1)=0$
$\Rightarrow(x-1)(5 x+2)=0$
$\Rightarrow(x-1)=0 \text { or } 5 x+2=0$
$⇒ x = 1$ or $\text{x}=-\frac{2}{5}$
$\therefore$ x = 1 and $\text{x}=-\frac{2}{5}$ are the two roots of the given equation.
$5 x^2-3 x-2=0$
$\Rightarrow 5 x^2-5 x+2 x-2=0$
$\Rightarrow 5 x(x-1)+2(x-1)=0$
$\Rightarrow(x-1)(5 x+2)=0$
$\Rightarrow(x-1)=0 \text { or } 5 x+2=0$
$⇒ x = 1$ or $\text{x}=-\frac{2}{5}$
$\therefore$ x = 1 and $\text{x}=-\frac{2}{5}$ are the two roots of the given equation.
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