Question
Solve the following quadratic equations by factorization:
$ 6 x^2+11 x+3=0 $

Answer

We have been given
$ 6 x^2+11 x+3=0 $
$ 6 x^2+9 x+2 x+3=0 $
$ 3 x(2 x+3)+1(2 x+3)=0 $
$ (2 x+3)(3 x+1)=0 $
$ 2 x+3=0$
$\text{x}=\frac{-3}{2}$
Or, $3x + 1 = 0$
$\text{x}=\frac{-1}{3}$
Hence, $\text{x}=\frac{-3}{2}$ or $\text{x}=\frac{-1}{3}$

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