Question
Solve the following systems of equations graphically:
$x + y = 4$
$2x - 3y = 3$
✓
Answer
The given equations are,
$x + y = 4 ......(i)$
$2x - 3y = 3 ........(ii)$
From $(i), y = 4 - x .......(iii)$
Putting $x = 0$ in $(iii)$, we get $y = 4$
Putting $x = 1$ in $(iii)$, we get $y = 3$
Putting $x = 2$ in $(iii)$, we get $y = 2$
From (ii), $\text{y}=\frac{2\text{x}-3}{3}\ ......(\text{iv})$
Putting $x = 0$ in $(iv)$, we get $y = -1$
Putting $x = 3$ in $(iv)$, we get $y = 1$
Putting $x = 6$ in $(iv)$, we get $y = 3$
Clearly, from the above graph solution of above syatam of equations is $x = 3$ and $y = 1.$
$x + y = 4 ......(i)$
$2x - 3y = 3 ........(ii)$
From $(i), y = 4 - x .......(iii)$
Putting $x = 0$ in $(iii)$, we get $y = 4$
Putting $x = 1$ in $(iii)$, we get $y = 3$
Putting $x = 2$ in $(iii)$, we get $y = 2$
|
$x$
|
$0$
|
$1$
|
$2$
|
|
$y$
|
$4$
|
$3$
|
$2$
|
Putting $x = 0$ in $(iv)$, we get $y = -1$
Putting $x = 3$ in $(iv)$, we get $y = 1$
Putting $x = 6$ in $(iv)$, we get $y = 3$
|
$x$
|
$0$
|
$3$
|
$6$
|
|
$y$
|
$-1$
|
$1$
|
$3$
|
Clearly, from the above graph solution of above syatam of equations is $x = 3$ and $y = 1.$
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