Question
Solve the inequation $\frac{2 \mathrm{x}+1}{3}+15 \leq 17 ; \mathrm{x} \in \mathrm{W}$.

Answer

$\frac{2 x+1}{3}+15 \leq 17 ; x \in W$
$ \Rightarrow \frac{2 x+1}{3} \leq 17-15=2$
$ \Rightarrow 2 x+1 \leq 6$
$ \Rightarrow 2 x \leq 5$
$ \Rightarrow x \leq \frac{5}{2}=2 \frac{1}{2}$
But $x \in W$
$\therefore \mathrm{x}=0,1,2$
$\therefore$ Solution set is $=\{0,1,2\}$

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