Question
Solve the system of inequality graphically: x $\ge$ 3, y $\ge$ 2
✓
Answer
The given inequality is $x \geqslant 3$.
Draw the graph of the line x = 3.
Putting (0, 0) in the given in equation, we have $0 \geqslant 3$ which is false.
$\therefore $ Half plane of $x \geqslant 3$ is away from origin.
Also the given inequality is $y \geqslant 2$
Draw the graph of the line y = 3.
Putting (0, 0) in the given inequation, we have $0 \geqslant 2$ which is false.
$\therefore $ Half plane of $y \geqslant 2$ is away from origin.
Draw the graph of the line x = 3.
Putting (0, 0) in the given in equation, we have $0 \geqslant 3$ which is false.
$\therefore $ Half plane of $x \geqslant 3$ is away from origin.
Also the given inequality is $y \geqslant 2$
Draw the graph of the line y = 3.
Putting (0, 0) in the given inequation, we have $0 \geqslant 2$ which is false.
$\therefore $ Half plane of $y \geqslant 2$ is away from origin.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Let r and n be positive integers such that 1 < r < n. Then prove the following: ${^\text{n}\text{C}}_{\text{r}}+2\ {^\text{n}\text{C}}_{\text{r}-1}+{^\text{n}\text{C}}_{\text{r}-2}={^\text{n+2}\text{C}}_{\text{r}}$
→Find the general solutions of the following equations: $3\cos^{2}\text{x}-2\sqrt{3}\sin\text{x}\cos\text{x}-3\sin^{2}\text{x}=0$
→Find the angles between the following pairs of straight lines: $\left(m^2-m n\right) y=\left(m n+n^2\right) x+n^3$ and $\left(m n+m^2\right) y=(m n-$ $\left.\mathrm{n}^2\right) \mathrm{x}+\mathrm{m}^3$.
→In $\triangle\text{ABC}$ prove that, it $\theta$ be any angle, then $\text{b}\cos\theta=\text{c}\cos(\text{A}-\theta)+\text{a}\cos(\text{C}+\theta).$
→Show that $\lim\limits_{\text{x}\rightarrow0}\ \sin\frac{1}{\text{x}}$ does not exist.
→Find the maximum and minimum values of each of the following trigonometrical expressions: $\sin\text{x}-\cos\text{x}+1$
→Find the sum of the series whose $n^{th}$ term is: $(2n - 1)^2$
→Differentiate the following from the first principle$\text{x}^2\text{e}{^\text{x}}$
→Find the sum of all two digit numbers which when divided by 4, yields 1 as remainder.
Prove the following identities: $\frac{\cos\text{x}}{1-\sin\text{x}}=\frac{1+\cos\text{x}+\sin\text{x}}{1+\cos\text{x}-\sin\text{x}}$
→