Solving – 8 5x – 3<7, we get: - Vidyadip

MCQ

Solving $ – 8 \leq 5\text{x} – 3<7, $ we get:

A
$\frac{–1}{2}\leq \text{x}\leq 2$
B
$1\leq \text{x}<2$
C
$ –1\leq\text{x}<2$
D
$ –1<\text{x}\leq2$

✓

Answer

$ –1\leq\text{x}<2$

Solution:

Given,

$-8\leq5\text{x}-3$ and $5\text{x}-3<7$

Let us solve these two inequalities simultaneously.

$-8\leq5\text{x}-3$ and $5\text{x}-3<7$ can be written as:

$– 8\leq5\text{x} –3 < 7$

Adding 3, we get

$– 8 + 3\leq5\text{x}-3+3<7+3$

$–5\leq5\text{x}<10$

Dividing by 5, we get

$–1\leq\text{x}<2$

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