MCQ
$s{p^3}$ hybridisation is found in
- A$CO_3^{2 - }$
- B$B{F_3}$
- C$NO_3^ - $
- ✓$N{H_3}$
Due to the presence of one lone pair, it is pyramidal in shape.
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| Energy level | $K$ | $L$ | $M$ | $N$ |
| $n=1$ | $n=2$ | $n=3$ | $n=4.....n=\infty$ | |
| Energy | $- 864 \,a.u.$ | Zero |
the excitation energy needed to raise the electron from $M$ level to $n = \infty$ would be :
(Given atomic masses of $A=64 ; B=40 ; C=32 u$ )