MCQ
$sp^3d^2$ hybrid orbitals have
- ✓${d_{{x^2} - {y^2}}}$ and ${d_{{z^2}}}$
- B${d_{xy}}$ and ${d_{{z^2}}}$
- C${d_{{x^2} - {y^2}}}$ and ${d_{{xy}}}$
- D${d_{yz}}$ and ${d_{{xz}}}$
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$C_2H_5OH_{(l)}+{3O_2} _{(g)} \rightarrow 2{CO_2} _{(g)}+3{H_2O}_{(l)}$
the amount of heat produced as measured in bomb calorimeter, is $1364.47\, kJ\, mol^{-1}$ at $25\,^oC.$ Assuming ideality the enthalpy of combustion, $\Delta_CH,$ for the reaction will be : $(R = 8.314\,kJ \,mol^{-1})$ .....$kJ\, mol^{-1}$
$(1)$ An electron in an orbital of high angular momentum stays away from the nucleus than an electron in the orbital of lower angular momentum.
$(2)$ For a given value of the principal quantum number, the size of the orbit is inversely proportional to the azimuthal quantum number
$(3)$ According to wave mechanics, the ground state angular momentum is equal to $\frac {h}{2\pi }$
$(4)$ The plot of $\Psi \,\,Vs\,\,r$ for various azimuthal quantum numbers, shows peak shifting towards higher $r$ value