Download App

8.2 Organic chemistry isomerism — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry8.2 Organic chemistry isomerism1 Mark
MCQ
Spin isomerism is shown by
  • A
    dichlorobenzene
  • ✓
    hydrogen
  • C
    dibasic acid
  • D
    $n-$ butane
✓

Answer

Correct option: B.
hydrogen
b
Spin isomerism is shown by hydrogen. In ortho-hydrogen, the spin of nuclei of two atoms of the molecule are in same direction whereas in case of para hydrogen, the spin of nuclei of two atoms are in opposite direction.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 8.2 Organic chemistry isomerism→8.2 Organic chemistry isomerism — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The electron affinity of
→
For the reaction $,\mathrm{NaCl}(\mathrm{s}) \rightarrow \mathrm{Na}^{+}(\mathrm{g})+\mathrm{Cl}^{-}(\mathrm{g})$ Identify the enthalpy involved in the above reaction :
→
On heating which of the following reliare $\ce{CO_2}$ easily
→
The standard electrode potential $E^-$ and its temperature coefficient $\left( {\frac{{d{E^ - }}}{{dT}}} \right)$ for a cell are $2\,V$ and $-\,5\times10^{-4}\,V\,K^{-1}$ at $300\,K$ respectively. The cell reaction is

$Zn\left( s \right) + C{u^{2 + }}\left( {aq} \right) \rightleftharpoons Z{n^{2 + }}\left( {aq} \right) + Cu\left( s \right)$

Standard reaction enthalpy $\left( {{\Delta _r}{H^ - }} \right)$ .......  $\mathrm{kJ}$

→
Identify the correct statement regarding a spontaneous process :
→
The stability order of oxide, peroxide and superoxide of alkaline metals is
→
$100\, \mathrm{~g}$ of propane is completely reacted with $1000\, \mathrm{~g}$ of oxygen. The mole fraction of carbon dioxide in the resulting mixture is $\mathrm{x} \times 10^{-2}$. The value of $\mathrm{x}$ is ..... .

(Nearest integer)

[Atomic weight : $\mathrm{H}=1.008 ; \mathrm{C}=12.00 ; \mathrm{O}=16.00$ ]

→
The reaction of $HBr$ with $\begin{array}{*{20}{c}}
  {\,\,\,\,\,C{H_3}} \\ 
  | \\ 
  {C{H_3} - C = C{H_2}} 
\end{array}$ in the presence of peroxide will give
→
During the fusion of an organic compound with sodium metal, nitrogen of the organic compound is converted into :
→
The reaction of $4$-methyloct-ene $P, 2.52 \mathrm{~g})$ with $\mathrm{HBr}$ in the presence of $\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}_2\right)_2 \mathrm{O}_2$ gives two isomeric bromides in a $9: 1$ ratio, with combined yield of $50 \%$. Of these, the entire amount of the primary alkyl bromide was reacted with an appropriate amount of diethylamine followed by treatment with eq. $\mathrm{K}_2 \mathrm{CO}_3$ to given a non-ionic product $\mathrm{S}$ in $100 \%$ yield.

The mass (in $\mathrm{mg}$ ) of $\mathrm{S}$ obtained is. . . . . . .  [Use molar mass (in g mol ${ }^{-1}$ ) : $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{Br}=80$ ]

→